Integrand size = 31, antiderivative size = 393 \[ \int \frac {\cos ^2(c+d x) (A+B \sec (c+d x))}{(a+b \sec (c+d x))^3} \, dx=\frac {\left (a^2 A+12 A b^2-6 a b B\right ) x}{2 a^5}-\frac {b^2 \left (20 a^4 A b-29 a^2 A b^3+12 A b^5-12 a^5 B+15 a^3 b^2 B-6 a b^4 B\right ) \text {arctanh}\left (\frac {\sqrt {a-b} \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a+b}}\right )}{a^5 (a-b)^{5/2} (a+b)^{5/2} d}-\frac {\left (6 a^4 A b-21 a^2 A b^3+12 A b^5-2 a^5 B+11 a^3 b^2 B-6 a b^4 B\right ) \sin (c+d x)}{2 a^4 \left (a^2-b^2\right )^2 d}+\frac {\left (a^4 A-10 a^2 A b^2+6 A b^4+6 a^3 b B-3 a b^3 B\right ) \cos (c+d x) \sin (c+d x)}{2 a^3 \left (a^2-b^2\right )^2 d}+\frac {b (A b-a B) \cos (c+d x) \sin (c+d x)}{2 a \left (a^2-b^2\right ) d (a+b \sec (c+d x))^2}+\frac {b \left (7 a^2 A b-4 A b^3-5 a^3 B+2 a b^2 B\right ) \cos (c+d x) \sin (c+d x)}{2 a^2 \left (a^2-b^2\right )^2 d (a+b \sec (c+d x))} \]
1/2*(A*a^2+12*A*b^2-6*B*a*b)*x/a^5-b^2*(20*A*a^4*b-29*A*a^2*b^3+12*A*b^5-1 2*B*a^5+15*B*a^3*b^2-6*B*a*b^4)*arctanh((a-b)^(1/2)*tan(1/2*d*x+1/2*c)/(a+ b)^(1/2))/a^5/(a-b)^(5/2)/(a+b)^(5/2)/d-1/2*(6*A*a^4*b-21*A*a^2*b^3+12*A*b ^5-2*B*a^5+11*B*a^3*b^2-6*B*a*b^4)*sin(d*x+c)/a^4/(a^2-b^2)^2/d+1/2*(A*a^4 -10*A*a^2*b^2+6*A*b^4+6*B*a^3*b-3*B*a*b^3)*cos(d*x+c)*sin(d*x+c)/a^3/(a^2- b^2)^2/d+1/2*b*(A*b-B*a)*cos(d*x+c)*sin(d*x+c)/a/(a^2-b^2)/d/(a+b*sec(d*x+ c))^2+1/2*b*(7*A*a^2*b-4*A*b^3-5*B*a^3+2*B*a*b^2)*cos(d*x+c)*sin(d*x+c)/a^ 2/(a^2-b^2)^2/d/(a+b*sec(d*x+c))
Time = 3.76 (sec) , antiderivative size = 734, normalized size of antiderivative = 1.87 \[ \int \frac {\cos ^2(c+d x) (A+B \sec (c+d x))}{(a+b \sec (c+d x))^3} \, dx=\frac {\frac {16 b^2 \left (20 a^4 A b-29 a^2 A b^3+12 A b^5-12 a^5 B+15 a^3 b^2 B-6 a b^4 B\right ) \text {arctanh}\left (\frac {(-a+b) \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{\left (a^2-b^2\right )^{5/2}}+\frac {4 a^8 A c+48 a^6 A b^2 c-12 a^4 A b^4 c-136 a^2 A b^6 c+96 A b^8 c-24 a^7 b B c+72 a^3 b^5 B c-48 a b^7 B c+4 a^8 A d x+48 a^6 A b^2 d x-12 a^4 A b^4 d x-136 a^2 A b^6 d x+96 A b^8 d x-24 a^7 b B d x+72 a^3 b^5 B d x-48 a b^7 B d x+16 a b \left (a^2-b^2\right )^2 \left (a^2 A+12 A b^2-6 a b B\right ) (c+d x) \cos (c+d x)+4 \left (a^3-a b^2\right )^2 \left (a^2 A+12 A b^2-6 a b B\right ) (c+d x) \cos (2 (c+d x))-8 a^7 A b \sin (c+d x)-32 a^5 A b^3 \sin (c+d x)+160 a^3 A b^5 \sin (c+d x)-96 a A b^7 \sin (c+d x)+4 a^8 B \sin (c+d x)+8 a^6 b^2 B \sin (c+d x)-84 a^4 b^4 B \sin (c+d x)+48 a^2 b^6 B \sin (c+d x)+2 a^8 A \sin (2 (c+d x))-48 a^6 A b^2 \sin (2 (c+d x))+130 a^4 A b^4 \sin (2 (c+d x))-72 a^2 A b^6 \sin (2 (c+d x))+16 a^7 b B \sin (2 (c+d x))-64 a^5 b^3 B \sin (2 (c+d x))+36 a^3 b^5 B \sin (2 (c+d x))-8 a^7 A b \sin (3 (c+d x))+16 a^5 A b^3 \sin (3 (c+d x))-8 a^3 A b^5 \sin (3 (c+d x))+4 a^8 B \sin (3 (c+d x))-8 a^6 b^2 B \sin (3 (c+d x))+4 a^4 b^4 B \sin (3 (c+d x))+a^8 A \sin (4 (c+d x))-2 a^6 A b^2 \sin (4 (c+d x))+a^4 A b^4 \sin (4 (c+d x))}{\left (a^2-b^2\right )^2 (b+a \cos (c+d x))^2}}{16 a^5 d} \]
((16*b^2*(20*a^4*A*b - 29*a^2*A*b^3 + 12*A*b^5 - 12*a^5*B + 15*a^3*b^2*B - 6*a*b^4*B)*ArcTanh[((-a + b)*Tan[(c + d*x)/2])/Sqrt[a^2 - b^2]])/(a^2 - b ^2)^(5/2) + (4*a^8*A*c + 48*a^6*A*b^2*c - 12*a^4*A*b^4*c - 136*a^2*A*b^6*c + 96*A*b^8*c - 24*a^7*b*B*c + 72*a^3*b^5*B*c - 48*a*b^7*B*c + 4*a^8*A*d*x + 48*a^6*A*b^2*d*x - 12*a^4*A*b^4*d*x - 136*a^2*A*b^6*d*x + 96*A*b^8*d*x - 24*a^7*b*B*d*x + 72*a^3*b^5*B*d*x - 48*a*b^7*B*d*x + 16*a*b*(a^2 - b^2)^ 2*(a^2*A + 12*A*b^2 - 6*a*b*B)*(c + d*x)*Cos[c + d*x] + 4*(a^3 - a*b^2)^2* (a^2*A + 12*A*b^2 - 6*a*b*B)*(c + d*x)*Cos[2*(c + d*x)] - 8*a^7*A*b*Sin[c + d*x] - 32*a^5*A*b^3*Sin[c + d*x] + 160*a^3*A*b^5*Sin[c + d*x] - 96*a*A*b ^7*Sin[c + d*x] + 4*a^8*B*Sin[c + d*x] + 8*a^6*b^2*B*Sin[c + d*x] - 84*a^4 *b^4*B*Sin[c + d*x] + 48*a^2*b^6*B*Sin[c + d*x] + 2*a^8*A*Sin[2*(c + d*x)] - 48*a^6*A*b^2*Sin[2*(c + d*x)] + 130*a^4*A*b^4*Sin[2*(c + d*x)] - 72*a^2 *A*b^6*Sin[2*(c + d*x)] + 16*a^7*b*B*Sin[2*(c + d*x)] - 64*a^5*b^3*B*Sin[2 *(c + d*x)] + 36*a^3*b^5*B*Sin[2*(c + d*x)] - 8*a^7*A*b*Sin[3*(c + d*x)] + 16*a^5*A*b^3*Sin[3*(c + d*x)] - 8*a^3*A*b^5*Sin[3*(c + d*x)] + 4*a^8*B*Si n[3*(c + d*x)] - 8*a^6*b^2*B*Sin[3*(c + d*x)] + 4*a^4*b^4*B*Sin[3*(c + d*x )] + a^8*A*Sin[4*(c + d*x)] - 2*a^6*A*b^2*Sin[4*(c + d*x)] + a^4*A*b^4*Sin [4*(c + d*x)])/((a^2 - b^2)^2*(b + a*Cos[c + d*x])^2))/(16*a^5*d)
Time = 2.87 (sec) , antiderivative size = 417, normalized size of antiderivative = 1.06, number of steps used = 19, number of rules used = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.581, Rules used = {3042, 4518, 25, 3042, 4588, 25, 3042, 4592, 27, 3042, 4592, 3042, 4407, 3042, 4318, 3042, 3138, 221}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \frac {\cos ^2(c+d x) (A+B \sec (c+d x))}{(a+b \sec (c+d x))^3} \, dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \int \frac {A+B \csc \left (c+d x+\frac {\pi }{2}\right )}{\csc \left (c+d x+\frac {\pi }{2}\right )^2 \left (a+b \csc \left (c+d x+\frac {\pi }{2}\right )\right )^3}dx\) |
| \(\Big \downarrow \) 4518 |
| \(\displaystyle \frac {b (A b-a B) \sin (c+d x) \cos (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \sec (c+d x))^2}-\frac {\int -\frac {\cos ^2(c+d x) \left (3 b (A b-a B) \sec ^2(c+d x)-2 a (A b-a B) \sec (c+d x)+2 \left (A a^2+b B a-2 A b^2\right )\right )}{(a+b \sec (c+d x))^2}dx}{2 a \left (a^2-b^2\right )}\) |
| \(\Big \downarrow \) 25 |
| \(\displaystyle \frac {\int \frac {\cos ^2(c+d x) \left (3 b (A b-a B) \sec ^2(c+d x)-2 a (A b-a B) \sec (c+d x)+2 \left (A a^2+b B a-2 A b^2\right )\right )}{(a+b \sec (c+d x))^2}dx}{2 a \left (a^2-b^2\right )}+\frac {b (A b-a B) \sin (c+d x) \cos (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \sec (c+d x))^2}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\int \frac {3 b (A b-a B) \csc \left (c+d x+\frac {\pi }{2}\right )^2-2 a (A b-a B) \csc \left (c+d x+\frac {\pi }{2}\right )+2 \left (A a^2+b B a-2 A b^2\right )}{\csc \left (c+d x+\frac {\pi }{2}\right )^2 \left (a+b \csc \left (c+d x+\frac {\pi }{2}\right )\right )^2}dx}{2 a \left (a^2-b^2\right )}+\frac {b (A b-a B) \sin (c+d x) \cos (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \sec (c+d x))^2}\) |
| \(\Big \downarrow \) 4588 |
| \(\displaystyle \frac {\frac {b \left (-5 a^3 B+7 a^2 A b+2 a b^2 B-4 A b^3\right ) \sin (c+d x) \cos (c+d x)}{a d \left (a^2-b^2\right ) (a+b \sec (c+d x))}-\frac {\int -\frac {\cos ^2(c+d x) \left (2 b \left (-5 B a^3+7 A b a^2+2 b^2 B a-4 A b^3\right ) \sec ^2(c+d x)-a \left (-2 B a^3+4 A b a^2-b^2 B a-A b^3\right ) \sec (c+d x)+2 \left (A a^4+6 b B a^3-10 A b^2 a^2-3 b^3 B a+6 A b^4\right )\right )}{a+b \sec (c+d x)}dx}{a \left (a^2-b^2\right )}}{2 a \left (a^2-b^2\right )}+\frac {b (A b-a B) \sin (c+d x) \cos (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \sec (c+d x))^2}\) |
| \(\Big \downarrow \) 25 |
| \(\displaystyle \frac {\frac {\int \frac {\cos ^2(c+d x) \left (2 b \left (-5 B a^3+7 A b a^2+2 b^2 B a-4 A b^3\right ) \sec ^2(c+d x)-a \left (-2 B a^3+4 A b a^2-b^2 B a-A b^3\right ) \sec (c+d x)+2 \left (A a^4+6 b B a^3-10 A b^2 a^2-3 b^3 B a+6 A b^4\right )\right )}{a+b \sec (c+d x)}dx}{a \left (a^2-b^2\right )}+\frac {b \left (-5 a^3 B+7 a^2 A b+2 a b^2 B-4 A b^3\right ) \sin (c+d x) \cos (c+d x)}{a d \left (a^2-b^2\right ) (a+b \sec (c+d x))}}{2 a \left (a^2-b^2\right )}+\frac {b (A b-a B) \sin (c+d x) \cos (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \sec (c+d x))^2}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\frac {\int \frac {2 b \left (-5 B a^3+7 A b a^2+2 b^2 B a-4 A b^3\right ) \csc \left (c+d x+\frac {\pi }{2}\right )^2-a \left (-2 B a^3+4 A b a^2-b^2 B a-A b^3\right ) \csc \left (c+d x+\frac {\pi }{2}\right )+2 \left (A a^4+6 b B a^3-10 A b^2 a^2-3 b^3 B a+6 A b^4\right )}{\csc \left (c+d x+\frac {\pi }{2}\right )^2 \left (a+b \csc \left (c+d x+\frac {\pi }{2}\right )\right )}dx}{a \left (a^2-b^2\right )}+\frac {b \left (-5 a^3 B+7 a^2 A b+2 a b^2 B-4 A b^3\right ) \sin (c+d x) \cos (c+d x)}{a d \left (a^2-b^2\right ) (a+b \sec (c+d x))}}{2 a \left (a^2-b^2\right )}+\frac {b (A b-a B) \sin (c+d x) \cos (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \sec (c+d x))^2}\) |
| \(\Big \downarrow \) 4592 |
| \(\displaystyle \frac {\frac {\frac {\left (a^4 A+6 a^3 b B-10 a^2 A b^2-3 a b^3 B+6 A b^4\right ) \sin (c+d x) \cos (c+d x)}{a d}-\frac {\int \frac {2 \cos (c+d x) \left (-2 B a^5+6 A b a^4+11 b^2 B a^3-21 A b^3 a^2-6 b^4 B a-\left (A a^4-4 b B a^3+4 A b^2 a^2+b^3 B a-2 A b^4\right ) \sec (c+d x) a+12 A b^5-b \left (A a^4+6 b B a^3-10 A b^2 a^2-3 b^3 B a+6 A b^4\right ) \sec ^2(c+d x)\right )}{a+b \sec (c+d x)}dx}{2 a}}{a \left (a^2-b^2\right )}+\frac {b \left (-5 a^3 B+7 a^2 A b+2 a b^2 B-4 A b^3\right ) \sin (c+d x) \cos (c+d x)}{a d \left (a^2-b^2\right ) (a+b \sec (c+d x))}}{2 a \left (a^2-b^2\right )}+\frac {b (A b-a B) \sin (c+d x) \cos (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \sec (c+d x))^2}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle \frac {\frac {\frac {\left (a^4 A+6 a^3 b B-10 a^2 A b^2-3 a b^3 B+6 A b^4\right ) \sin (c+d x) \cos (c+d x)}{a d}-\frac {\int \frac {\cos (c+d x) \left (-2 B a^5+6 A b a^4+11 b^2 B a^3-21 A b^3 a^2-6 b^4 B a-\left (A a^4-4 b B a^3+4 A b^2 a^2+b^3 B a-2 A b^4\right ) \sec (c+d x) a+12 A b^5-b \left (A a^4+6 b B a^3-10 A b^2 a^2-3 b^3 B a+6 A b^4\right ) \sec ^2(c+d x)\right )}{a+b \sec (c+d x)}dx}{a}}{a \left (a^2-b^2\right )}+\frac {b \left (-5 a^3 B+7 a^2 A b+2 a b^2 B-4 A b^3\right ) \sin (c+d x) \cos (c+d x)}{a d \left (a^2-b^2\right ) (a+b \sec (c+d x))}}{2 a \left (a^2-b^2\right )}+\frac {b (A b-a B) \sin (c+d x) \cos (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \sec (c+d x))^2}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\frac {\frac {\left (a^4 A+6 a^3 b B-10 a^2 A b^2-3 a b^3 B+6 A b^4\right ) \sin (c+d x) \cos (c+d x)}{a d}-\frac {\int \frac {-2 B a^5+6 A b a^4+11 b^2 B a^3-21 A b^3 a^2-6 b^4 B a-\left (A a^4-4 b B a^3+4 A b^2 a^2+b^3 B a-2 A b^4\right ) \csc \left (c+d x+\frac {\pi }{2}\right ) a+12 A b^5-b \left (A a^4+6 b B a^3-10 A b^2 a^2-3 b^3 B a+6 A b^4\right ) \csc \left (c+d x+\frac {\pi }{2}\right )^2}{\csc \left (c+d x+\frac {\pi }{2}\right ) \left (a+b \csc \left (c+d x+\frac {\pi }{2}\right )\right )}dx}{a}}{a \left (a^2-b^2\right )}+\frac {b \left (-5 a^3 B+7 a^2 A b+2 a b^2 B-4 A b^3\right ) \sin (c+d x) \cos (c+d x)}{a d \left (a^2-b^2\right ) (a+b \sec (c+d x))}}{2 a \left (a^2-b^2\right )}+\frac {b (A b-a B) \sin (c+d x) \cos (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \sec (c+d x))^2}\) |
| \(\Big \downarrow \) 4592 |
| \(\displaystyle \frac {\frac {\frac {\left (a^4 A+6 a^3 b B-10 a^2 A b^2-3 a b^3 B+6 A b^4\right ) \sin (c+d x) \cos (c+d x)}{a d}-\frac {\frac {\left (-2 a^5 B+6 a^4 A b+11 a^3 b^2 B-21 a^2 A b^3-6 a b^4 B+12 A b^5\right ) \sin (c+d x)}{a d}-\frac {\int \frac {\left (A a^2-6 b B a+12 A b^2\right ) \left (a^2-b^2\right )^2+a b \left (A a^4+6 b B a^3-10 A b^2 a^2-3 b^3 B a+6 A b^4\right ) \sec (c+d x)}{a+b \sec (c+d x)}dx}{a}}{a}}{a \left (a^2-b^2\right )}+\frac {b \left (-5 a^3 B+7 a^2 A b+2 a b^2 B-4 A b^3\right ) \sin (c+d x) \cos (c+d x)}{a d \left (a^2-b^2\right ) (a+b \sec (c+d x))}}{2 a \left (a^2-b^2\right )}+\frac {b (A b-a B) \sin (c+d x) \cos (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \sec (c+d x))^2}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\frac {\frac {\left (a^4 A+6 a^3 b B-10 a^2 A b^2-3 a b^3 B+6 A b^4\right ) \sin (c+d x) \cos (c+d x)}{a d}-\frac {\frac {\left (-2 a^5 B+6 a^4 A b+11 a^3 b^2 B-21 a^2 A b^3-6 a b^4 B+12 A b^5\right ) \sin (c+d x)}{a d}-\frac {\int \frac {\left (A a^2-6 b B a+12 A b^2\right ) \left (a^2-b^2\right )^2+a b \left (A a^4+6 b B a^3-10 A b^2 a^2-3 b^3 B a+6 A b^4\right ) \csc \left (c+d x+\frac {\pi }{2}\right )}{a+b \csc \left (c+d x+\frac {\pi }{2}\right )}dx}{a}}{a}}{a \left (a^2-b^2\right )}+\frac {b \left (-5 a^3 B+7 a^2 A b+2 a b^2 B-4 A b^3\right ) \sin (c+d x) \cos (c+d x)}{a d \left (a^2-b^2\right ) (a+b \sec (c+d x))}}{2 a \left (a^2-b^2\right )}+\frac {b (A b-a B) \sin (c+d x) \cos (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \sec (c+d x))^2}\) |
| \(\Big \downarrow \) 4407 |
| \(\displaystyle \frac {\frac {\frac {\left (a^4 A+6 a^3 b B-10 a^2 A b^2-3 a b^3 B+6 A b^4\right ) \sin (c+d x) \cos (c+d x)}{a d}-\frac {\frac {\left (-2 a^5 B+6 a^4 A b+11 a^3 b^2 B-21 a^2 A b^3-6 a b^4 B+12 A b^5\right ) \sin (c+d x)}{a d}-\frac {\frac {x \left (a^2-b^2\right )^2 \left (a^2 A-6 a b B+12 A b^2\right )}{a}-\frac {b^2 \left (-12 a^5 B+20 a^4 A b+15 a^3 b^2 B-29 a^2 A b^3-6 a b^4 B+12 A b^5\right ) \int \frac {\sec (c+d x)}{a+b \sec (c+d x)}dx}{a}}{a}}{a}}{a \left (a^2-b^2\right )}+\frac {b \left (-5 a^3 B+7 a^2 A b+2 a b^2 B-4 A b^3\right ) \sin (c+d x) \cos (c+d x)}{a d \left (a^2-b^2\right ) (a+b \sec (c+d x))}}{2 a \left (a^2-b^2\right )}+\frac {b (A b-a B) \sin (c+d x) \cos (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \sec (c+d x))^2}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\frac {\frac {\left (a^4 A+6 a^3 b B-10 a^2 A b^2-3 a b^3 B+6 A b^4\right ) \sin (c+d x) \cos (c+d x)}{a d}-\frac {\frac {\left (-2 a^5 B+6 a^4 A b+11 a^3 b^2 B-21 a^2 A b^3-6 a b^4 B+12 A b^5\right ) \sin (c+d x)}{a d}-\frac {\frac {x \left (a^2-b^2\right )^2 \left (a^2 A-6 a b B+12 A b^2\right )}{a}-\frac {b^2 \left (-12 a^5 B+20 a^4 A b+15 a^3 b^2 B-29 a^2 A b^3-6 a b^4 B+12 A b^5\right ) \int \frac {\csc \left (c+d x+\frac {\pi }{2}\right )}{a+b \csc \left (c+d x+\frac {\pi }{2}\right )}dx}{a}}{a}}{a}}{a \left (a^2-b^2\right )}+\frac {b \left (-5 a^3 B+7 a^2 A b+2 a b^2 B-4 A b^3\right ) \sin (c+d x) \cos (c+d x)}{a d \left (a^2-b^2\right ) (a+b \sec (c+d x))}}{2 a \left (a^2-b^2\right )}+\frac {b (A b-a B) \sin (c+d x) \cos (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \sec (c+d x))^2}\) |
| \(\Big \downarrow \) 4318 |
| \(\displaystyle \frac {\frac {\frac {\left (a^4 A+6 a^3 b B-10 a^2 A b^2-3 a b^3 B+6 A b^4\right ) \sin (c+d x) \cos (c+d x)}{a d}-\frac {\frac {\left (-2 a^5 B+6 a^4 A b+11 a^3 b^2 B-21 a^2 A b^3-6 a b^4 B+12 A b^5\right ) \sin (c+d x)}{a d}-\frac {\frac {x \left (a^2-b^2\right )^2 \left (a^2 A-6 a b B+12 A b^2\right )}{a}-\frac {b \left (-12 a^5 B+20 a^4 A b+15 a^3 b^2 B-29 a^2 A b^3-6 a b^4 B+12 A b^5\right ) \int \frac {1}{\frac {a \cos (c+d x)}{b}+1}dx}{a}}{a}}{a}}{a \left (a^2-b^2\right )}+\frac {b \left (-5 a^3 B+7 a^2 A b+2 a b^2 B-4 A b^3\right ) \sin (c+d x) \cos (c+d x)}{a d \left (a^2-b^2\right ) (a+b \sec (c+d x))}}{2 a \left (a^2-b^2\right )}+\frac {b (A b-a B) \sin (c+d x) \cos (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \sec (c+d x))^2}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\frac {\frac {\left (a^4 A+6 a^3 b B-10 a^2 A b^2-3 a b^3 B+6 A b^4\right ) \sin (c+d x) \cos (c+d x)}{a d}-\frac {\frac {\left (-2 a^5 B+6 a^4 A b+11 a^3 b^2 B-21 a^2 A b^3-6 a b^4 B+12 A b^5\right ) \sin (c+d x)}{a d}-\frac {\frac {x \left (a^2-b^2\right )^2 \left (a^2 A-6 a b B+12 A b^2\right )}{a}-\frac {b \left (-12 a^5 B+20 a^4 A b+15 a^3 b^2 B-29 a^2 A b^3-6 a b^4 B+12 A b^5\right ) \int \frac {1}{\frac {a \sin \left (c+d x+\frac {\pi }{2}\right )}{b}+1}dx}{a}}{a}}{a}}{a \left (a^2-b^2\right )}+\frac {b \left (-5 a^3 B+7 a^2 A b+2 a b^2 B-4 A b^3\right ) \sin (c+d x) \cos (c+d x)}{a d \left (a^2-b^2\right ) (a+b \sec (c+d x))}}{2 a \left (a^2-b^2\right )}+\frac {b (A b-a B) \sin (c+d x) \cos (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \sec (c+d x))^2}\) |
| \(\Big \downarrow \) 3138 |
| \(\displaystyle \frac {\frac {\frac {\left (a^4 A+6 a^3 b B-10 a^2 A b^2-3 a b^3 B+6 A b^4\right ) \sin (c+d x) \cos (c+d x)}{a d}-\frac {\frac {\left (-2 a^5 B+6 a^4 A b+11 a^3 b^2 B-21 a^2 A b^3-6 a b^4 B+12 A b^5\right ) \sin (c+d x)}{a d}-\frac {\frac {x \left (a^2-b^2\right )^2 \left (a^2 A-6 a b B+12 A b^2\right )}{a}-\frac {2 b \left (-12 a^5 B+20 a^4 A b+15 a^3 b^2 B-29 a^2 A b^3-6 a b^4 B+12 A b^5\right ) \int \frac {1}{\left (1-\frac {a}{b}\right ) \tan ^2\left (\frac {1}{2} (c+d x)\right )+\frac {a+b}{b}}d\tan \left (\frac {1}{2} (c+d x)\right )}{a d}}{a}}{a}}{a \left (a^2-b^2\right )}+\frac {b \left (-5 a^3 B+7 a^2 A b+2 a b^2 B-4 A b^3\right ) \sin (c+d x) \cos (c+d x)}{a d \left (a^2-b^2\right ) (a+b \sec (c+d x))}}{2 a \left (a^2-b^2\right )}+\frac {b (A b-a B) \sin (c+d x) \cos (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \sec (c+d x))^2}\) |
| \(\Big \downarrow \) 221 |
| \(\displaystyle \frac {b (A b-a B) \sin (c+d x) \cos (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \sec (c+d x))^2}+\frac {\frac {b \left (-5 a^3 B+7 a^2 A b+2 a b^2 B-4 A b^3\right ) \sin (c+d x) \cos (c+d x)}{a d \left (a^2-b^2\right ) (a+b \sec (c+d x))}+\frac {\frac {\left (a^4 A+6 a^3 b B-10 a^2 A b^2-3 a b^3 B+6 A b^4\right ) \sin (c+d x) \cos (c+d x)}{a d}-\frac {\frac {\left (-2 a^5 B+6 a^4 A b+11 a^3 b^2 B-21 a^2 A b^3-6 a b^4 B+12 A b^5\right ) \sin (c+d x)}{a d}-\frac {\frac {x \left (a^2-b^2\right )^2 \left (a^2 A-6 a b B+12 A b^2\right )}{a}-\frac {2 b^2 \left (-12 a^5 B+20 a^4 A b+15 a^3 b^2 B-29 a^2 A b^3-6 a b^4 B+12 A b^5\right ) \text {arctanh}\left (\frac {\sqrt {a-b} \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a+b}}\right )}{a d \sqrt {a-b} \sqrt {a+b}}}{a}}{a}}{a \left (a^2-b^2\right )}}{2 a \left (a^2-b^2\right )}\) |
(b*(A*b - a*B)*Cos[c + d*x]*Sin[c + d*x])/(2*a*(a^2 - b^2)*d*(a + b*Sec[c + d*x])^2) + ((b*(7*a^2*A*b - 4*A*b^3 - 5*a^3*B + 2*a*b^2*B)*Cos[c + d*x]* Sin[c + d*x])/(a*(a^2 - b^2)*d*(a + b*Sec[c + d*x])) + (((a^4*A - 10*a^2*A *b^2 + 6*A*b^4 + 6*a^3*b*B - 3*a*b^3*B)*Cos[c + d*x]*Sin[c + d*x])/(a*d) - (-((((a^2 - b^2)^2*(a^2*A + 12*A*b^2 - 6*a*b*B)*x)/a - (2*b^2*(20*a^4*A*b - 29*a^2*A*b^3 + 12*A*b^5 - 12*a^5*B + 15*a^3*b^2*B - 6*a*b^4*B)*ArcTanh[ (Sqrt[a - b]*Tan[(c + d*x)/2])/Sqrt[a + b]])/(a*Sqrt[a - b]*Sqrt[a + b]*d) )/a) + ((6*a^4*A*b - 21*a^2*A*b^3 + 12*A*b^5 - 2*a^5*B + 11*a^3*b^2*B - 6* a*b^4*B)*Sin[c + d*x])/(a*d))/a)/(a*(a^2 - b^2)))/(2*a*(a^2 - b^2))
3.4.35.3.1 Defintions of rubi rules used
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x /Rt[-a/b, 2]], x] /; FreeQ[{a, b}, x] && NegQ[a/b]
Int[((a_) + (b_.)*sin[Pi/2 + (c_.) + (d_.)*(x_)])^(-1), x_Symbol] :> With[{ e = FreeFactors[Tan[(c + d*x)/2], x]}, Simp[2*(e/d) Subst[Int[1/(a + b + (a - b)*e^2*x^2), x], x, Tan[(c + d*x)/2]/e], x]] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - b^2, 0]
Int[csc[(e_.) + (f_.)*(x_)]/(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_)), x_Symbo l] :> Simp[1/b Int[1/(1 + (a/b)*Sin[e + f*x]), x], x] /; FreeQ[{a, b, e, f}, x] && NeQ[a^2 - b^2, 0]
Int[(csc[(e_.) + (f_.)*(x_)]*(d_.) + (c_))/(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_)), x_Symbol] :> Simp[c*(x/a), x] - Simp[(b*c - a*d)/a Int[Csc[e + f* x]/(a + b*Csc[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*c - a*d, 0]
Int[(csc[(e_.) + (f_.)*(x_)]*(d_.))^(n_)*(csc[(e_.) + (f_.)*(x_)]*(b_.) + ( a_))^(m_)*(csc[(e_.) + (f_.)*(x_)]*(B_.) + (A_)), x_Symbol] :> Simp[b*(A*b - a*B)*Cot[e + f*x]*(a + b*Csc[e + f*x])^(m + 1)*((d*Csc[e + f*x])^n/(a*f*( m + 1)*(a^2 - b^2))), x] + Simp[1/(a*(m + 1)*(a^2 - b^2)) Int[(a + b*Csc[ e + f*x])^(m + 1)*(d*Csc[e + f*x])^n*Simp[A*(a^2*(m + 1) - b^2*(m + n + 1)) + a*b*B*n - a*(A*b - a*B)*(m + 1)*Csc[e + f*x] + b*(A*b - a*B)*(m + n + 2) *Csc[e + f*x]^2, x], x], x] /; FreeQ[{a, b, d, e, f, A, B, n}, x] && NeQ[A* b - a*B, 0] && NeQ[a^2 - b^2, 0] && LtQ[m, -1] && !(ILtQ[m + 1/2, 0] && IL tQ[n, 0])
Int[((A_.) + csc[(e_.) + (f_.)*(x_)]*(B_.) + csc[(e_.) + (f_.)*(x_)]^2*(C_. ))*(csc[(e_.) + (f_.)*(x_)]*(d_.))^(n_)*(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a _))^(m_), x_Symbol] :> Simp[(A*b^2 - a*b*B + a^2*C)*Cot[e + f*x]*(a + b*Csc [e + f*x])^(m + 1)*((d*Csc[e + f*x])^n/(a*f*(m + 1)*(a^2 - b^2))), x] + Sim p[1/(a*(m + 1)*(a^2 - b^2)) Int[(a + b*Csc[e + f*x])^(m + 1)*(d*Csc[e + f *x])^n*Simp[a*(a*A - b*B + a*C)*(m + 1) - (A*b^2 - a*b*B + a^2*C)*(m + n + 1) - a*(A*b - a*B + b*C)*(m + 1)*Csc[e + f*x] + (A*b^2 - a*b*B + a^2*C)*(m + n + 2)*Csc[e + f*x]^2, x], x], x] /; FreeQ[{a, b, d, e, f, A, B, C, n}, x ] && NeQ[a^2 - b^2, 0] && LtQ[m, -1] && !(ILtQ[m + 1/2, 0] && ILtQ[n, 0])
Int[((A_.) + csc[(e_.) + (f_.)*(x_)]*(B_.) + csc[(e_.) + (f_.)*(x_)]^2*(C_. ))*(csc[(e_.) + (f_.)*(x_)]*(d_.))^(n_)*(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a _))^(m_), x_Symbol] :> Simp[A*Cot[e + f*x]*(a + b*Csc[e + f*x])^(m + 1)*((d *Csc[e + f*x])^n/(a*f*n)), x] + Simp[1/(a*d*n) Int[(a + b*Csc[e + f*x])^m *(d*Csc[e + f*x])^(n + 1)*Simp[a*B*n - A*b*(m + n + 1) + a*(A + A*n + C*n)* Csc[e + f*x] + A*b*(m + n + 2)*Csc[e + f*x]^2, x], x], x] /; FreeQ[{a, b, d , e, f, A, B, C, m}, x] && NeQ[a^2 - b^2, 0] && LeQ[n, -1]
Time = 2.00 (sec) , antiderivative size = 403, normalized size of antiderivative = 1.03
| method | result | size |
| derivativedivides | \(\frac {\frac {2 b^{2} \left (\frac {-\frac {\left (10 A \,a^{2} b +A a \,b^{2}-6 A \,b^{3}-8 B \,a^{3}-B \,a^{2} b +4 B a \,b^{2}\right ) a b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{2 \left (a -b \right ) \left (a^{2}+2 a b +b^{2}\right )}+\frac {b a \left (10 A \,a^{2} b -A a \,b^{2}-6 A \,b^{3}-8 B \,a^{3}+B \,a^{2} b +4 B a \,b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{2 \left (a +b \right ) \left (a -b \right )^{2}}}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} a -\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} b -a -b \right )^{2}}-\frac {\left (20 A \,a^{4} b -29 A \,a^{2} b^{3}+12 A \,b^{5}-12 B \,a^{5}+15 B \,a^{3} b^{2}-6 B a \,b^{4}\right ) \operatorname {arctanh}\left (\frac {\left (a -b \right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{\sqrt {\left (a -b \right ) \left (a +b \right )}}\right )}{2 \left (a^{4}-2 a^{2} b^{2}+b^{4}\right ) \sqrt {\left (a -b \right ) \left (a +b \right )}}\right )}{a^{5}}+\frac {\frac {2 \left (\left (-\frac {1}{2} A \,a^{2}-3 A a b +B \,a^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}+\left (\frac {1}{2} A \,a^{2}-3 A a b +B \,a^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{\left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )^{2}}+\left (A \,a^{2}+12 A \,b^{2}-6 B a b \right ) \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a^{5}}}{d}\) | \(403\) |
| default | \(\frac {\frac {2 b^{2} \left (\frac {-\frac {\left (10 A \,a^{2} b +A a \,b^{2}-6 A \,b^{3}-8 B \,a^{3}-B \,a^{2} b +4 B a \,b^{2}\right ) a b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{2 \left (a -b \right ) \left (a^{2}+2 a b +b^{2}\right )}+\frac {b a \left (10 A \,a^{2} b -A a \,b^{2}-6 A \,b^{3}-8 B \,a^{3}+B \,a^{2} b +4 B a \,b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{2 \left (a +b \right ) \left (a -b \right )^{2}}}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} a -\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} b -a -b \right )^{2}}-\frac {\left (20 A \,a^{4} b -29 A \,a^{2} b^{3}+12 A \,b^{5}-12 B \,a^{5}+15 B \,a^{3} b^{2}-6 B a \,b^{4}\right ) \operatorname {arctanh}\left (\frac {\left (a -b \right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{\sqrt {\left (a -b \right ) \left (a +b \right )}}\right )}{2 \left (a^{4}-2 a^{2} b^{2}+b^{4}\right ) \sqrt {\left (a -b \right ) \left (a +b \right )}}\right )}{a^{5}}+\frac {\frac {2 \left (\left (-\frac {1}{2} A \,a^{2}-3 A a b +B \,a^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}+\left (\frac {1}{2} A \,a^{2}-3 A a b +B \,a^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{\left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )^{2}}+\left (A \,a^{2}+12 A \,b^{2}-6 B a b \right ) \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a^{5}}}{d}\) | \(403\) |
| risch | \(\text {Expression too large to display}\) | \(1509\) |
1/d*(2*b^2/a^5*((-1/2*(10*A*a^2*b+A*a*b^2-6*A*b^3-8*B*a^3-B*a^2*b+4*B*a*b^ 2)*a*b/(a-b)/(a^2+2*a*b+b^2)*tan(1/2*d*x+1/2*c)^3+1/2*b*a*(10*A*a^2*b-A*a* b^2-6*A*b^3-8*B*a^3+B*a^2*b+4*B*a*b^2)/(a+b)/(a-b)^2*tan(1/2*d*x+1/2*c))/( tan(1/2*d*x+1/2*c)^2*a-tan(1/2*d*x+1/2*c)^2*b-a-b)^2-1/2*(20*A*a^4*b-29*A* a^2*b^3+12*A*b^5-12*B*a^5+15*B*a^3*b^2-6*B*a*b^4)/(a^4-2*a^2*b^2+b^4)/((a- b)*(a+b))^(1/2)*arctanh((a-b)*tan(1/2*d*x+1/2*c)/((a-b)*(a+b))^(1/2)))+2/a ^5*(((-1/2*A*a^2-3*A*a*b+B*a^2)*tan(1/2*d*x+1/2*c)^3+(1/2*A*a^2-3*A*a*b+B* a^2)*tan(1/2*d*x+1/2*c))/(1+tan(1/2*d*x+1/2*c)^2)^2+1/2*(A*a^2+12*A*b^2-6* B*a*b)*arctan(tan(1/2*d*x+1/2*c))))
Leaf count of result is larger than twice the leaf count of optimal. 875 vs. \(2 (373) = 746\).
Time = 0.44 (sec) , antiderivative size = 1811, normalized size of antiderivative = 4.61 \[ \int \frac {\cos ^2(c+d x) (A+B \sec (c+d x))}{(a+b \sec (c+d x))^3} \, dx=\text {Too large to display} \]
[1/4*(2*(A*a^10 - 6*B*a^9*b + 9*A*a^8*b^2 + 18*B*a^7*b^3 - 33*A*a^6*b^4 - 18*B*a^5*b^5 + 35*A*a^4*b^6 + 6*B*a^3*b^7 - 12*A*a^2*b^8)*d*x*cos(d*x + c) ^2 + 4*(A*a^9*b - 6*B*a^8*b^2 + 9*A*a^7*b^3 + 18*B*a^6*b^4 - 33*A*a^5*b^5 - 18*B*a^4*b^6 + 35*A*a^3*b^7 + 6*B*a^2*b^8 - 12*A*a*b^9)*d*x*cos(d*x + c) + 2*(A*a^8*b^2 - 6*B*a^7*b^3 + 9*A*a^6*b^4 + 18*B*a^5*b^5 - 33*A*a^4*b^6 - 18*B*a^3*b^7 + 35*A*a^2*b^8 + 6*B*a*b^9 - 12*A*b^10)*d*x - (12*B*a^5*b^4 - 20*A*a^4*b^5 - 15*B*a^3*b^6 + 29*A*a^2*b^7 + 6*B*a*b^8 - 12*A*b^9 + (12 *B*a^7*b^2 - 20*A*a^6*b^3 - 15*B*a^5*b^4 + 29*A*a^4*b^5 + 6*B*a^3*b^6 - 12 *A*a^2*b^7)*cos(d*x + c)^2 + 2*(12*B*a^6*b^3 - 20*A*a^5*b^4 - 15*B*a^4*b^5 + 29*A*a^3*b^6 + 6*B*a^2*b^7 - 12*A*a*b^8)*cos(d*x + c))*sqrt(a^2 - b^2)* log((2*a*b*cos(d*x + c) - (a^2 - 2*b^2)*cos(d*x + c)^2 - 2*sqrt(a^2 - b^2) *(b*cos(d*x + c) + a)*sin(d*x + c) + 2*a^2 - b^2)/(a^2*cos(d*x + c)^2 + 2* a*b*cos(d*x + c) + b^2)) + 2*(2*B*a^8*b^2 - 6*A*a^7*b^3 - 13*B*a^6*b^4 + 2 7*A*a^5*b^5 + 17*B*a^4*b^6 - 33*A*a^3*b^7 - 6*B*a^2*b^8 + 12*A*a*b^9 + (A* a^10 - 3*A*a^8*b^2 + 3*A*a^6*b^4 - A*a^4*b^6)*cos(d*x + c)^3 + 2*(B*a^10 - 2*A*a^9*b - 3*B*a^8*b^2 + 6*A*a^7*b^3 + 3*B*a^6*b^4 - 6*A*a^5*b^5 - B*a^4 *b^6 + 2*A*a^3*b^7)*cos(d*x + c)^2 + (4*B*a^9*b - 11*A*a^8*b^2 - 20*B*a^7* b^3 + 43*A*a^6*b^4 + 25*B*a^5*b^5 - 50*A*a^4*b^6 - 9*B*a^3*b^7 + 18*A*a^2* b^8)*cos(d*x + c))*sin(d*x + c))/((a^13 - 3*a^11*b^2 + 3*a^9*b^4 - a^7*b^6 )*d*cos(d*x + c)^2 + 2*(a^12*b - 3*a^10*b^3 + 3*a^8*b^5 - a^6*b^7)*d*co...
\[ \int \frac {\cos ^2(c+d x) (A+B \sec (c+d x))}{(a+b \sec (c+d x))^3} \, dx=\int \frac {\left (A + B \sec {\left (c + d x \right )}\right ) \cos ^{2}{\left (c + d x \right )}}{\left (a + b \sec {\left (c + d x \right )}\right )^{3}}\, dx \]
Exception generated. \[ \int \frac {\cos ^2(c+d x) (A+B \sec (c+d x))}{(a+b \sec (c+d x))^3} \, dx=\text {Exception raised: ValueError} \]
Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'assume' command before evaluation *may* help (example of legal syntax is 'assume(4*a^2-4*b^2>0)', see `assume?` f or more de
Leaf count of result is larger than twice the leaf count of optimal. 2700 vs. \(2 (373) = 746\).
Time = 0.64 (sec) , antiderivative size = 2700, normalized size of antiderivative = 6.87 \[ \int \frac {\cos ^2(c+d x) (A+B \sec (c+d x))}{(a+b \sec (c+d x))^3} \, dx=\text {Too large to display} \]
-1/2*(((a^6 - a^5*b + 10*a^4*b^2 + 10*a^3*b^3 - 23*a^2*b^4 - 6*a*b^5 + 12* b^6)*sqrt(-a^2 + b^2)*A*abs(a^9 - 2*a^7*b^2 + a^5*b^4)*abs(-a + b) - 3*(2* a^5*b + 2*a^4*b^2 - 4*a^3*b^3 - a^2*b^4 + 2*a*b^5)*sqrt(-a^2 + b^2)*B*abs( a^9 - 2*a^7*b^2 + a^5*b^4)*abs(-a + b) - (a^15 - a^14*b + 8*a^13*b^2 - 28* a^12*b^3 - 42*a^11*b^4 + 111*a^10*b^5 + 68*a^9*b^6 - 158*a^8*b^7 - 47*a^7* b^8 + 100*a^6*b^9 + 12*a^5*b^10 - 24*a^4*b^11)*sqrt(-a^2 + b^2)*A*abs(-a + b) + 3*(2*a^14*b - 6*a^13*b^2 - 8*a^12*b^3 + 21*a^11*b^4 + 12*a^10*b^5 - 28*a^9*b^6 - 8*a^8*b^7 + 17*a^7*b^8 + 2*a^6*b^9 - 4*a^5*b^10)*sqrt(-a^2 + b^2)*B*abs(-a + b))*(pi*floor(1/2*(d*x + c)/pi + 1/2) + arctan(tan(1/2*d*x + 1/2*c)/sqrt(-(a^8*b - 2*a^6*b^3 + a^4*b^5 + sqrt((a^9 + a^8*b - 2*a^7*b ^2 - 2*a^6*b^3 + a^5*b^4 + a^4*b^5)*(a^9 - a^8*b - 2*a^7*b^2 + 2*a^6*b^3 + a^5*b^4 - a^4*b^5) + (a^8*b - 2*a^6*b^3 + a^4*b^5)^2))/(a^9 - a^8*b - 2*a ^7*b^2 + 2*a^6*b^3 + a^5*b^4 - a^4*b^5))))/((a^9 - 2*a^7*b^2 + a^5*b^4)^2* (a^2 - 2*a*b + b^2) + (a^10*b - 2*a^9*b^2 - a^8*b^3 + 4*a^7*b^4 - a^6*b^5 - 2*a^5*b^6 + a^4*b^7)*abs(a^9 - 2*a^7*b^2 + a^5*b^4)) + (A*a^15 - A*a^14* b - 6*B*a^14*b + 8*A*a^13*b^2 + 18*B*a^13*b^2 - 28*A*a^12*b^3 + 24*B*a^12* b^3 - 42*A*a^11*b^4 - 63*B*a^11*b^4 + 111*A*a^10*b^5 - 36*B*a^10*b^5 + 68* A*a^9*b^6 + 84*B*a^9*b^6 - 158*A*a^8*b^7 + 24*B*a^8*b^7 - 47*A*a^7*b^8 - 5 1*B*a^7*b^8 + 100*A*a^6*b^9 - 6*B*a^6*b^9 + 12*A*a^5*b^10 + 12*B*a^5*b^10 - 24*A*a^4*b^11 + A*a^6*abs(a^9 - 2*a^7*b^2 + a^5*b^4) - A*a^5*b*abs(a^...
Time = 27.62 (sec) , antiderivative size = 10586, normalized size of antiderivative = 26.94 \[ \int \frac {\cos ^2(c+d x) (A+B \sec (c+d x))}{(a+b \sec (c+d x))^3} \, dx=\text {Too large to display} \]
((tan(c/2 + (d*x)/2)^5*(3*A*a^7 - 36*A*b^7 - 2*B*a^7 + 67*A*a^2*b^5 - 29*A *a^3*b^4 - 26*A*a^4*b^3 + 5*A*a^5*b^2 - 9*B*a^2*b^5 - 35*B*a^3*b^4 + 16*B* a^4*b^3 + 10*B*a^5*b^2 + 18*A*a*b^6 + 4*A*a^6*b + 18*B*a*b^6 - 4*B*a^6*b)) /((a + b)^2*(a^6 - 2*a^5*b + a^4*b^2)) - (tan(c/2 + (d*x)/2)^3*(3*A*a^7 + 36*A*b^7 + 2*B*a^7 - 67*A*a^2*b^5 - 29*A*a^3*b^4 + 26*A*a^4*b^3 + 5*A*a^5* b^2 - 9*B*a^2*b^5 + 35*B*a^3*b^4 + 16*B*a^4*b^3 - 10*B*a^5*b^2 + 18*A*a*b^ 6 - 4*A*a^6*b - 18*B*a*b^6 - 4*B*a^6*b))/((a + b)^2*(a^6 - 2*a^5*b + a^4*b ^2)) + (tan(c/2 + (d*x)/2)^7*(A*a^6 - 12*A*b^6 - 2*B*a^6 + 23*A*a^2*b^4 - 10*A*a^3*b^3 - 8*A*a^4*b^2 - 3*B*a^2*b^4 - 12*B*a^3*b^3 + 4*B*a^4*b^2 + 6* A*a*b^5 + 5*A*a^5*b + 6*B*a*b^5 + 2*B*a^5*b))/((a^4*b - a^5)*(a + b)^2) + (tan(c/2 + (d*x)/2)*(A*a^6 - 12*A*b^6 + 2*B*a^6 + 23*A*a^2*b^4 + 10*A*a^3* b^3 - 8*A*a^4*b^2 + 3*B*a^2*b^4 - 12*B*a^3*b^3 - 4*B*a^4*b^2 - 6*A*a*b^5 - 5*A*a^5*b + 6*B*a*b^5 + 2*B*a^5*b))/((a + b)*(a^6 - 2*a^5*b + a^4*b^2)))/ (d*(2*a*b - tan(c/2 + (d*x)/2)^4*(2*a^2 - 6*b^2) + tan(c/2 + (d*x)/2)^2*(4 *a*b + 4*b^2) - tan(c/2 + (d*x)/2)^6*(4*a*b - 4*b^2) + tan(c/2 + (d*x)/2)^ 8*(a^2 - 2*a*b + b^2) + a^2 + b^2)) + (atan(((((8*tan(c/2 + (d*x)/2)*(A^2* a^14 + 288*A^2*b^14 - 288*A^2*a*b^13 - 2*A^2*a^13*b - 1104*A^2*a^2*b^12 + 1104*A^2*a^3*b^11 + 1538*A^2*a^4*b^10 - 1538*A^2*a^5*b^9 - 827*A^2*a^6*b^8 + 872*A^2*a^7*b^7 + 18*A^2*a^8*b^6 - 108*A^2*a^9*b^5 + 74*A^2*a^10*b^4 - 40*A^2*a^11*b^3 + 21*A^2*a^12*b^2 + 72*B^2*a^2*b^12 - 72*B^2*a^3*b^11 -...